Question

If a current of 0.5 ampere flows through a metallic wire for 2 hours, then how many electrons would flow through the wire?

Answer 1

Q=It

Where Q= no. of electron

I= current

t= time taken

$Q=0.5A\times 72005$

$=3600C$

As $96487C=6.023\times {10}^{23}$ no. of electron

$\Rightarrow 3600C=\frac{6.023\times {10}^{23}\times 3600}{96487}=2.25\times {10}^{22}$ no. of electron