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The equation of the parabola is of the form $y_{2}=4ax$ (as it is opening to the right)

Given, diameter of parabola $=20$ cm

Since, parabola is symmetric about $x$-axis.

So, co-ordinates of point $A$ are $(5,10)$

Since the parabola passes through the point $A(5,10)$

Since the parabola passes through the point $A(5,10)$

$10_{2}=4a(5)$

$⇒100=20a$

$⇒a=20100 =5$

Therefore, the focus of the parabola is $(a,0)=(5,0)$ which is the mid-point of the diameter.

$⇒100=20a$

$⇒a=20100 =5$

Therefore, the focus of the parabola is $(a,0)=(5,0)$ which is the mid-point of the diameter.

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