If A={(x,y):x2+y2=25} and B={(x,y):x2+9y2=144}; then A∩B contains
one point
three points
two points
four points
A
three points
B
one point
C
two points
D
four points
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Solution
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Clearly, A is the set of all points on the circle x2+y2=25 and B is the set of all points on the ellipse x2+9y2=144. These two intersect at four points P,Q,R and S. Hence, A∩B contains four points.
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