0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

If a33a2b+3ab2b3 is divided by (ab), then the remainder is
  1. a2ab+b2
  2. a2+ab+b2
  3. 1
  4. 0

A
a2ab+b2
B
a2+ab+b2
C
1
D
0
Solution
Verified by Toppr

The remainder is equal to f(b) by remainder theorem.
f(b)=b33b2.b+3b.b2b3=0
Thus it comes out to be 0.

Was this answer helpful?
2
Similar Questions
Q1
a3+3a2b+3ab2+b3 divided by a2+2ab+b2 is
View Solution
Q2
If a33a2b+3ab2b3 is divided by (ab), then the remainder is
View Solution
Q3

If a3+b3=27 and a2+b2ab=9, then a+b=___

View Solution
Q4
If x=1+a+a2+a3+.... to (|a|<1) and
y=1+b+b2+b3+... to (|b|<1) then
1+ab+a2b2+a3b3+... to =xyx+y1
View Solution
Q5
Factorise aa3+b3b is _______
View Solution