If AB - CD- angle APQ -50-o and angle PRD -127-o- then x and y respectively are -40-o- 30-o50-o- 77-o30-o- 45-o90-o- 30-o

Question

Toppr Admin · Accepted Answer

-x2220-x-x2220-APQ -xA0- -x2235-AB-CD- as given in question-x-50-x2218-x2220-PRQ-180-x2212-x2220-PRD-x21D2-x2220-PRQ-180-x2212-127-53-x2218-x2234-y-180-x2212-x-x2212-x2220-PRQ-x21D2-y-180-x2212-50-x2212-53-x21D2-y-77-x2218-

If $A B$ $| |$ $C D$ , $∠ A P Q$ $= 50^{o}$ and $∠$ $P R D$ $= 127^{o}$ , then $x$ and $y$ respectively are ___________.

$40^{o}, 30^{o}$
$50^{o}, 77^{o}$
$30^{o}, 45^{o}$
$90^{o}, 30^{o}$

$∠ x = ∠ A P Q$ ( $∵ A B | | C D$ , as given in question)
$x = 50^{\circ}$
$∠ P R Q = 180 - ∠ P R D \Rightarrow ∠ P R Q = 180 - 127 = 53^{\circ}$
$∴ y = 180 - x - ∠ P R Q \Rightarrow y = 180 - 50 - 53 \Rightarrow y = 77^{\circ}$

If AB || CD, ∠APQ =50o and ∠ PRD =127o, then x and y respectively are ___________.40o,30o50o,77o30o,45o90o,30o

∠x=∠APQ (∵AB||CD, as given in question)x=50∘∠PRQ=180−∠PRD⇒∠PRQ=180−127=53∘∴y=180−x−∠PRQ⇒y=180−50−53⇒y=77∘

If $A B$ $| |$ $C D$ , $∠ A P Q$ $= 50^{o}$ and $∠$ $P R D$ $= 127^{o}$ , then $x$ and $y$ respectively are ___________.

$40^{o}, 30^{o}$
$50^{o}, 77^{o}$
$30^{o}, 45^{o}$
$90^{o}, 30^{o}$

$∠ x = ∠ A P Q$ ( $∵ A B | | C D$ , as given in question)
$x = 50^{\circ}$
$∠ P R Q = 180 - ∠ P R D \Rightarrow ∠ P R Q = 180 - 127 = 53^{\circ}$
$∴ y = 180 - x - ∠ P R Q \Rightarrow y = 180 - 50 - 53 \Rightarrow y = 77^{\circ}$