If ABCD is a rectangle- E- F are the mid-points of BC and AD respectively and G is any point on EF- then triangle GAB equals-displaystylefrac-1-2-Box ABCD-displaystylefrac-1-4-Box ABCD-displaystylefrac-1-3-Box ABCD-displaystylefrac-1-6-Box ABCD-

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Given that E and F are mid-points of BC and AD respectively-ar-x25A1-ABFE-12ar-x25A1-ABCD-x2235- E and F are mid points of BC and AD respectively-ar-x25B3-GAB-12ar-x25A1-ABFE-x2235- Area of triangle is half of area of rectangle on the same base and between the same parallels-12-xD7-12ar-x25A1-ABCD-14ar-x25A1-ABCD-

If ABCD is a rectangle, E,F are the mid-points of BC and AD respectively and G is any point on EF, then △GAB equals.12(□ABCD)14(□ABCD)13(□ABCD)16(□ABCD)

Given that E and F are mid-points of BC and AD respectively.ar(□ABFE)=12ar(□ABCD)[∵ E and F are mid points of BC and AD respectively]ar(△GAB)=12ar(□ABFE)[∵ Area of triangle is half of area of rectangle on the same base and between the same parallels]=12×12ar(□ABCD)=14ar(□ABCD)

If $A B C D$ is a rectangle, $E, F$ are the mid-points of $B C$ and $A D$ respectively and $G$ is any point on $E F$ , then $△ G A B$ equals.
$\frac{1}{2} (□ A B C D)$
$\frac{1}{4} (□ A B C D)$
$\frac{1}{3} (□ A B C D)$
$\frac{1}{6} (□ A B C D)$