If an electron describes half a revolution in a circle of radius r in a magnetic field B, the energy acquired by it is
zero
$\frac{1}{2} m v^{2}$
$\frac{1}{4} m v^{2}$
$μ_{r} \times B e v$

Question

If an electron describes half a revolution in a circle of radius r in a magnetic field B- the energy acquired by it iszerodisplaystyle frac-1-2- mv-2displaystyle frac-1-4- mv-2mu-r times Bev

Toppr Admin · Accepted Answer

Since magnetic force is always perpendicular to the velocity of electron-So it can only change the direction of velocity of electron-But it -the magnetic force- cannot accelerate or deaccelerate the electron-

If an electron describes half a revolution in a circle of radius r in a magnetic field B, the energy acquired by it iszero12mv214mv2μr×Bev

Since magnetic force is always perpendicular to the velocity of electron.So it can only change the direction of velocity of electron.But it (the magnetic force) cannot accelerate or deaccelerate the electron.

If an electron describes half a revolution in a circle of radius r in a magnetic field B, the energy acquired by it is
zero
$\frac{1}{2} m v^{2}$
$\frac{1}{4} m v^{2}$
$μ_{r} \times B e v$

Since magnetic force is always perpendicular to the velocity of electron.
So it can only change the direction of velocity of electron.
But it (the magnetic force) cannot accelerate or deaccelerate the electron.