If an electron of velocity is 2i-4j is subjected to magnetic field of 4k- then- the electron -speed will changevelocity is Constantpath will changemomentum is Constant

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Toppr Admin · Accepted Answer

F-q-x2192-V-xD7-x2192-B-e-2i-4j-xD7-4k-e-x2212-8j-16i-xA0-xA0-xA0-xA0-xA0-xA0-xA0-xA0-xA0- -By cross-product rule-So- it has non-zero force- so it velocity direction changes so- path changes- velocity changes- momentum changes but magnitude of velocity is constant- so- speed remains constant-

If an electron of velocity is $2 i + 4 j$ is subjected to magnetic field of $4 k$ , then, for the electron ,
speed will change
velocity is Constant
path will change
momentum is Constant

$F = q (\to V \times \to B)$
$= e [(2 i + 4 j) \times 4 k]$
$= e [- 8 j + 16 i]$ (By cross-product rule)
So, it has non-zero force, so it velocity direction changes so, path changes, velocity changes, momentum changes but magnitude of velocity is constant, so, speed remains constant.

If an electron of velocity is 2i+4j is subjected to magnetic field of 4k, then, for the electron ,speed will changevelocity is Constantpath will changemomentum is Constant

F=q(→V×→B)=e[(2i+4j)×4k]=e[−8j+16i] (By cross-product rule)So, it has non-zero force, so it velocity direction changes so, path changes, velocity changes, momentum changes but magnitude of velocity is constant, so, speed remains constant.

If an electron of velocity is $2 i + 4 j$ is subjected to magnetic field of $4 k$ , then, for the electron ,
speed will change
velocity is Constant
path will change
momentum is Constant

$F = q (\to V \times \to B)$
$= e [(2 i + 4 j) \times 4 k]$
$= e [- 8 j + 16 i]$ (By cross-product rule)
So, it has non-zero force, so it velocity direction changes so, path changes, velocity changes, momentum changes but magnitude of velocity is constant, so, speed remains constant.