If an electron of velocity is $2 i + 4 j$ is subjected to magnetic field of $4 k$ , then, for the electron ,

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Answer 1

$F = q (V \times B)$
$= e [(2 i + 4 j) \times 4 k]$
$= e [- 8 j + 16 i]$ (By cross-product rule)
So, it has non-zero force, so it velocity direction changes so, path changes, velocity changes, momentum changes but magnitude of velocity is constant, so, speed remains constant.

Answer 2

F = q (V \times B)

= e [(2 i + 4 j) \times 4 k]

= e [- 8 j + 16 i]

(By cross-product rule)
So, it has non-zero force, so it velocity direction changes so, path changes, velocity changes, momentum changes but magnitude of velocity is constant, so, speed remains constant.

If an electron of velocity is $2 i + 4 j$ is subjected to magnetic field of $4 k$ , then, for the electron ,

speed will change

path will change

velocity is Constant

momentum is Constant

$F = q (V \times B)$
$= e [(2 i + 4 j) \times 4 k]$
$= e [- 8 j + 16 i]$ (By cross-product rule)
So, it has non-zero force, so it velocity direction changes so, path changes, velocity changes, momentum changes but magnitude of velocity is constant, so, speed remains constant.

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Revise with Concepts

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If an electron of velocity is 2i+4j is subjected to magnetic field of 4k, then, for the electron ,

speed will change

path will change

velocity is Constant

momentum is Constant

F=q(V×B) =e[(2i+4j)×4k] =e[−8j+16i] (By cross-product rule) So, it has non-zero force, so it velocity direction changes so, path changes, velocity changes, momentum changes but magnitude of velocity is constant, so, speed remains constant.

When a charged particle moving with velocity V is subjected to a magnetic field of induction B, the force on it is non-zero. This implies the

A uniform electric field and a uniform magnetic field exist in a region in the same direction. An electron is projected with velocity pointed in the same direction the electron will

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Revise with Concepts

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If an electron of velocity is $2 i + 4 j$ is subjected to magnetic field of $4 k$ , then, for the electron ,

$F = q (V \times B)$
$= e [(2 i + 4 j) \times 4 k]$
$= e [- 8 j + 16 i]$ (By cross-product rule)
So, it has non-zero force, so it velocity direction changes so, path changes, velocity changes, momentum changes but magnitude of velocity is constant, so, speed remains constant.

When a charged particle moving with velocity $V$ is subjected to a magnetic field of induction $B$ , the force on it is non-zero. This implies the

If electron velocity is $2 \hat{i} + 3 \hat{j}$ and it is subjected to magnetic field of $4 \hat{k},$ then its