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Question

If an electron of velocity is 2i+4j is subjected to magnetic field of 4k, then, for the electron ,
  1. speed will change
  2. velocity is Constant
  3. path will change
  4. momentum is Constant

A
path will change
B
speed will change
C
momentum is Constant
D
velocity is Constant
Solution
Verified by Toppr

F=q(V×B)
=e[(2i+4j)×4k]
=e[8j+16i] (By cross-product rule)
So, it has non-zero force, so it velocity direction changes so, path changes, velocity changes, momentum changes but magnitude of velocity is constant, so, speed remains constant.

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