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# If an electron of velocity is 2i+4j is subjected to magnetic field of 4k, then, for the electron ,speed will changevelocity is Constantpath will changemomentum is Constant

A
path will change
B
speed will change
C
momentum is Constant
D
velocity is Constant
Solution
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#### F=q(→V×→B)=e[(2i+4j)×4k]=e[−8j+16i] (By cross-product rule)So, it has non-zero force, so it velocity direction changes so, path changes, velocity changes, momentum changes but magnitude of velocity is constant, so, speed remains constant.

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