If an uncharged capacitor is charged by connecting it to a battery, then the amount of energy lost as heat is:
12QV
12QV2
QV
QV2
A
QV2
B
12QV
C
12QV2
D
QV
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Solution
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The charge stored on capacitor =Q
We know, if Q charge has passed through battery work done by battery =QV
Energy stored in capacitor =12CV2=12QV [∵Q=CV]
∴ Energy lost as heat = Work done by battery −Energy store in capacitor
=QV−12QV=12QV
Hence, option A is correct.
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