If angles of a triangle are in the ratio 2-3-4- Find the value of each angle-

Question

Toppr Admin · Accepted Answer

Let common ratio be 2x-3x and 4x-x2192- let common ratio be x-x2234-xA0- Angle are 2x-xA0-3x and 4x-x2234-xA0-2x-3x4x-180o-x2234-xA0-9x-180o-x2234-xA0-x-180o9-20o-x2234-xA0- Angle are 40o-xA0-60o-xA0-80o

If angles of a triangle are in the ratio $2 : 3 : 4$ . Find the value of each angle.

Let common ratio be $2 x, 3 x$ and $4 x$
$\to$ let common ratio be $x$
$∴$ Angle are $2 x, 3 x$ and $4 x$
$∴ 2 x + 3 x 4 x = 180^{o}$
$∴ 9 x = 180^{o}$
$∴ x = \frac{180^{o}}{9} = 20^{o}$
$∴$ Angle are $40^{o}, 60^{o}, 80^{o}$

If angles of a triangle are in the ratio 2:3:4. Find the value of each angle.

Let common ratio be 2x,3x and 4x→ let common ratio be x∴ Angle are 2x, 3x and 4x∴ 2x+3x4x=180o∴ 9x=180o∴ x=180o9=20o∴ Angle are 40o, 60o, 80o

If angles of a triangle are in the ratio $2 : 3 : 4$ . Find the value of each angle.

Let common ratio be $2 x, 3 x$ and $4 x$
$\to$ let common ratio be $x$
$∴$ Angle are $2 x, 3 x$ and $4 x$
$∴ 2 x + 3 x 4 x = 180^{o}$
$∴ 9 x = 180^{o}$
$∴ x = \frac{180^{o}}{9} = 20^{o}$
$∴$ Angle are $40^{o}, 60^{o}, 80^{o}$