Question

If another liquid is filled instead of water, the object and the image coincide at a distance $25cm$ from the lens. Calculate the refractive index of the liquid.

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Updated on : 2022-09-05

Solution

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Correct option is A)

Consider refraction from first surface,

$2v_{1}3 −−251 =R23 −1 $

Consider refraction from second surface, where image of first acts as its

object.

$v_{2}μ −2v_{1}3 =−Rμ−23 $

As explained above, $v_{2}=−∞$

Thus solving the above equations for $R=10cm$ as found previously gives $μ=1.6$

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