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If another liquid is filled instead of water, the object and the image coincide at a distance 25 cm from the lens. Calculate the refractive index of the liquid.

- 1.6
- 2.6
- 2.8
- 3.2

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Solution

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Consider refraction from first surface,

32v1−1−25=32−1R

Consider refraction from second surface, where image of first acts as its

object.

μv2−32v1=μ−32−R

As explained above, v2=−∞

Thus solving the above equations for R=10cm as found previously gives μ=1.6

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