If atomic number of inert gas is Z- then ionic bond is formed between-Z - 1- and -Z - 1-Z - 2- and -Z - 2-both -a- and -b-none of these

Question

Toppr Admin · Accepted Answer

If Z is the atomic number of the inert gas- then-z-x2212-1-x21D2-halogens-z-1-alkalimetals-z-x2212-2-x21D2-oxygenfamily-z-2-alkalineearthmetals-Fromioniccompound

If atomic number of inert gas is $Z$ , then ionic bond is formed between:
$(Z - 1)$ and $(Z + 1)$
$(Z - 2)$ and $(Z + 2)$
both (a) and (b)
none of these

If Z is the atomic number of the inert gas, then
$\begin{matrix} (z - 1) & \Rightarrow & h a l o g e n s (z + 1) = a l k a l i m e t a l s (z - 2) & \Rightarrow & o x y g e n f a m i l y; (z + 2) = a l k a l i n e e a r t h m e t a l s \end{matrix}} F r o m i o n i c c o m p o u n d$

If atomic number of inert gas is Z, then ionic bond is formed between:(Z−1) and (Z+1)(Z−2) and (Z+2)both (a) and (b)none of these

If Z is the atomic number of the inert gas, then(z−1)⇒halogens(z+1)=alkalimetals(z−2)⇒oxygenfamily;(z+2)=alkalineearthmetals}Fromioniccompound

If atomic number of inert gas is $Z$ , then ionic bond is formed between:
$(Z - 1)$ and $(Z + 1)$
$(Z - 2)$ and $(Z + 2)$
both (a) and (b)
none of these

If Z is the atomic number of the inert gas, then
$\begin{matrix} (z - 1) & \Rightarrow & h a l o g e n s (z + 1) = a l k a l i m e t a l s (z - 2) & \Rightarrow & o x y g e n f a m i l y; (z + 2) = a l k a l i n e e a r t h m e t a l s \end{matrix}} F r o m i o n i c c o m p o u n d$