If C and R denote capacitance and resistance- then dimensions of CR will bedisplaystyle left - ML-0-TA-2- right -displaystyle left - M-0-L-0-TA-0- right -displaystyle left - ML-0-TA-2- right -displaystyle left - ML-0-T-2-A-2- right -

Question

Toppr Admin · Accepted Answer

We know that value RC gives time constant in an R-x2212-C circuit and that V-t-V0e-x2212-tRCExponents are always dimensionless- thus -x2212-tRC-M0L0T0A0 or -RC-t-M0L0T1A0-

If $C$ and $R$ denote capacitance and resistance, then dimensions of $C R$ will be
$[M L^{0} T A^{2}]$
$[M^{0} L^{0} T A^{0}]$
$[M L^{0} T A^{- 2}]$
$[M L^{0} T^{2} A^{- 2}]$

We know that value $R C$ gives time constant in an $R - C$ circuit and that $V (t) = V_{0} e^{\frac{- t}{R C}}$
Exponents are always dimensionless, thus $[\frac{- t}{R C}] = M^{0} L^{0} T^{0} A^{0}$ or $[R C] = [t] = [M^{0} L^{0} T^{1} A^{0}]$

If C and R denote capacitance and resistance, then dimensions of CR will be[ML0TA2][M0L0TA0][ML0TA−2][ML0T2A−2]

We know that value RC gives time constant in an R−C circuit and that V(t)=V0e−tRCExponents are always dimensionless, thus [−tRC]=M0L0T0A0 or [RC]=[t]=[M0L0T1A0]

If $C$ and $R$ denote capacitance and resistance, then dimensions of $C R$ will be
$[M L^{0} T A^{2}]$
$[M^{0} L^{0} T A^{0}]$
$[M L^{0} T A^{- 2}]$
$[M L^{0} T^{2} A^{- 2}]$

We know that value $R C$ gives time constant in an $R - C$ circuit and that $V (t) = V_{0} e^{\frac{- t}{R C}}$
Exponents are always dimensionless, thus $[\frac{- t}{R C}] = M^{0} L^{0} T^{0} A^{0}$ or $[R C] = [t] = [M^{0} L^{0} T^{1} A^{0}]$