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Dimensions and Dimensional Analysis

Question

If C be the capacitance and V be the electric potential,then the dimensional formula of $$ CV^2 $$ is

A

$$ [ML ^{-3} TA] $$

B

$$ [ML ^1 A^{-1 }] $$

C

$$ [ML^2T^{-2} A^o] $$

D

$$ [M^oLT^{-2} A^o] $$

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Solution

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Correct option is D. $$ [ML^2T^{-2} A^o] $$

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