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Standard XI
Maths
Question
If
4
n
+
1
.2
n
−
8
n
2
2
n
=
3
8
, then
n
=
−
1
−
3
−
2
−
4
A
−
3
B
−
1
C
−
2
D
−
4
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Solution
Verified by Toppr
4
n
+
1
.2
n
−
8
n
2
2
n
=
3
8
Let
2
n
=
t
⇒
4.4
n
.2
n
−
(
2
3
)
n
(
2
n
)
2
=
3
8
⇒
4.
t
3
−
t
3
t
2
=
3
8
⇒
3
t
=
3
8
⇒
t
=
2
−
3
⇒
2
n
=
2
−
3
⇒
n
=
−
3
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