Solve

Guides

0

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Question

If $\frac{a}{b + c} = \frac{b}{c + a} = \frac{c}{a + b}$ , then each of the ratio is?
$1 / 2$ or $- 1$
$1 / 2$ or $2$
$1$
$- 1$ or $- 1 / 2$

A

- 1

or

- 1 / 2

B

1 / 2

or

2

C

1

D

1 / 2

or

- 1

Open in App

Solution

Verified by Toppr

$\frac{a}{b} = \frac{b}{c} = \frac{c}{a} = k$
Also, $\frac{a}{b + c} = \frac{b}{c + a}$
$\Rightarrow \frac{b k}{b + {b k}^{2}} = \frac{h}{{b k}^{2} + b k}$
$\Rightarrow \frac{k}{1 + k^{2}} = \frac{1}{k^{2} + k} \Rightarrow k = 1$

Was this answer helpful?

0

Similar Questions

Q1

If

\frac{a}{b + c} = \frac{b}{c + a} = \frac{c}{a + b}

, then prove that each ratio is equal to

\frac{1}{2}

or

- 1

.

View Solution

Q2

If

\frac{a}{b + c} = \frac{b}{c + a} = \frac{c}{a + b} = r

then, r cannot take any value except :(CAT 2004)

View Solution

Q3

If A = {a, b, c, d}, B={1, 2, 3}, find whether or not the following sets of ordered pairs are relations from A to B or not
(a)

R_{1}

={(a, 1), (a, 3)}
(b)

R_{2}

= { (b, 1), (c, 2), (d, 1)}
(c)

R_{3}

= {(a, 1), (b, 2),( 3, c)}

View Solution

Q4

Solve the absolute value equation

4 | 2 x - 1 | - 2 = 10

View Solution

Q5

If

x^{2} + 2 (k + 2) x + 9 k = 0

has a repeated root, then k = ?
(a) 1 or 4
(b) −1 or 4
(c) 1 or −4
(d) −1 or −4

View Solution