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Question

If xa2xb2=x16,x>1, and a+b=2, what is the value of ab?
  1. 8
  2. 14
  3. 16
  4. 18

A
18
B
8
C
14
D
16
Solution
Verified by Toppr

Given, xa2xb2=x16
Also given, x>1 and a+b=2 ..(1)
xa2b2=x16
a2b2=16 ...(2) (When the non-zero base is the same, the index also must be the same)
Dividing equations (1) and (2),
a2b2a+b=ab=162=8

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