If E-a- be the electric field intensity due to a short dipole a point on the axis and E-r- be that on the right bisector the same distance from the dipole- thenE-a- -2E-r-E-r- -2E-a-E-a- -E-r-E-a- -sqrt-2-E-r-

Question

Toppr Admin · Accepted Answer

If q be the charge on one point of the dipole and the half length is equal to d-then the total dipole moment is given by- p - 2qdIf Ea be the field at any axial point- then it is given by-xA0-kpr3Similarly- the field at any point on the right bisector-xA0-is given Er-kp2r3Hence- Ea-2Er

If Ea be the electric field intensity due to a short dipole at a point on the axis and Er be that on the right bisector at the same distance from the dipole, thenEa=2ErEr=2EaEa=ErEa=√2Er

If q be the charge on one point of the dipole and the half length is equal to d,then the total dipole moment is given by, p = 2qdIf Ea be the field at any axial point, then it is given by kpr3Similarly, the field at any point on the right bisector is given Er=kp2r3Hence, Ea=2Er

If $E_{a}$ be the electric field intensity due to a short dipole at a point on the axis and $E_{r}$ be that on the right bisector at the same distance from the dipole, then
$E_{a} = 2 E_{r}$
$E_{r} = 2 E_{a}$
$E_{a} = E_{r}$
$E_{a} = \sqrt{2} E_{r}$