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# If each diode in figure has forward bias resistance of $$25 \Omega$$ and infinite resistance in reverse bias , what will be the value of current $$I_1 , I_2 , I_3$$ and $$I_4$$ ?

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#### $$I_3$$ is zero as the diode in that branch is reverse biased. Resistance in the branch AB and EF are each $$(125 + 25)\Omega = 150 \Omega$$ As AB and EF are identical parallel branches , their effective resistance is $$\dfrac{150}{2} = 75 \Omega$$ $$\therefore \,$$ Net resistance in the circuit = $$(75 + 25) \Omega = 100 \, \Omega$$ $$\therefore \,$$ Current $$I_1 = \dfrac{5}{100} = 0.05 \,A$$ AS resistance of AB and EF are equal and $$I_1 = I_2 + I_3 + I_4 , I_3 = 0$$ $$\therefore \, I_2 = I_4 = \dfrac{0.05}{2} = 0.025\,A$$

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If each diode in figure has forward bias resistance of $$25 \Omega$$ and infinite resistance in reverse bias , what will be the value of current $$I_1 , I_2 , I_3$$ and $$I_4$$ ?

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