Question

If effective length of a simple pendulum is equal to radius of earth (R), time period will be

A
T=πRg
B
T=2π2Rg
C
T=2πRg
D
T=2πR2g
Solution
Verified by Toppr

formula,

T=2πLRg(R+L)

If the effective length of a simple pendulum is equal to the radius of the earth (R),

then,

T=2πR×Rg(R+R)

=2πR2g(2R)

T=2πR2g

Was this answer helpful?
6
Similar Questions
Q1

A disc is suspended at a point R2 above its center, Find its period of oscillation.


View Solution
Q2

A particle of charge -q & mass m moves in a circle of radius r around an infinitely long line charge having linear charge density +λ. Then time period will be--


View Solution
Q3

The period T of a simple pendulum is T=2πlg the maximum error in T due to possible errors upto 1% in l and 2.5% in g is

View Solution
Q4

Periodic time (T) of a satellite revolving above Earth’s surface at a height equal to the radius of Earth (R), is
g = 9.8m/s2

View Solution
Q5

Time period T of a simple pendulum of length l is given by
T=2πlg. If the length is increased by 2%, then an approximate change in the time period is

View Solution
Solve
Guides