If electron velocity is $2 \hat{i} + 3 \hat{j}$ and it is subjected to magnetic field of $4 \hat{k},$ then its

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Answer 1

since magnetic field is perpendicular to the direction of option or the velocity vector of the electron. therefore, the force will always act perpendicular to the both direction of magnetic field as well as velocity vector of electron and electron will do a circular motion since magnetic field is uniform.
Hence only direction of motion will change.

Answer 2

since magnetic field is perpendicular to the direction of option or the velocity vector of the electron. therefore, the force will always act perpendicular to the both direction of magnetic field as well as velocity vector of electron and electron will do a circular motion since magnetic field is uniform.
Hence only direction of motion will change.

If electron velocity is $2 \hat{i} + 3 \hat{j}$ and it is subjected to magnetic field of $4 \hat{k},$ then its

speed will change

path will change

both (a) and (b)

none of these

An experimenters diary reads as follows : A charged particle is projected in a magnetic field $(7 \hat{i} - 3 \hat{j}) \times 1 0^{- 3}$ T . The acceleration of the particle is found to be $(\hat{i} + 7 \hat{j}) \times 1 0^{- 6} m s^{- 2}$ then coefficient of $\hat{i}$ is

A charged particle moves with a constant velocity $(\hat{i} + \hat{j}) m / s$ in a magnetic field $B = (2 \hat{i} + 3 \hat{k})$ and uniform electric field $E = (a \hat{i} + b \hat{j} + c \hat{k}) N / C$ , then $($ assuming all quantities in S.I. unit $) :$

If an electron of velocity is $2 i + 4 j$ is subjected to magnetic field of $4 k$ , then, for the electron ,

A proton moving with a velocity of $(6 \hat{i} + 8 \hat{j}) \times 1 0^{5} m s^{- 1}$ enters uniform magnetic field of induction $5 \times 1 0^{- 3} \hat{k} T$ . The magnitude of the force acting on the proton is :
( $\hat{i}, \hat{j}$ and $\hat{k}$ are unit vectors forming a right handed triad)

Revise with Concepts

Motion in the Presence of Magnetic Field

Motion in the Presence of Magnetic Field - Problems L1

If electron velocity is 2i^+3j^​ and it is subjected to magnetic field of 4k^, then its

speed will change

path will change

both (a) and (b)

none of these

An experimenters diary reads as follows : A charged particle is projected in a magnetic field (7i^−3j^​)×10−3T . The acceleration of the particle is found to be (i^+7j^​)×10−6ms−2 then coefficient of i^ is

A particle of charge +q and mass m moving under the influence of a uniform electric field Ei^ and uniform magnetic field Bk^ follows a trajectory from P to Q as shown in figure. The velocities at P and Q are vi^ and −2vj^​. Among the following the correct statements is/are :

A charged particle moves with a constant velocity (i^+j^​)m/s in a magnetic field B=(2i^+3k^) and uniform electric field E=(ai^+bj^​+ck^)N/C , then (assuming all quantities in S.I. unit):

If an electron of velocity is 2i+4j is subjected to magnetic field of 4k, then, for the electron ,

A proton moving with a velocity of (6i^+8j^​)×105 ms−1 enters uniform magnetic field of induction 5×10−3k^T . The magnitude of the force acting on the proton is : (i^,j^​ and k^ are unit vectors forming a right handed triad)

Revise with Concepts

Motion in the Presence of Magnetic Field

Motion in the Presence of Magnetic Field - Problems L1

If electron velocity is $2 \hat{i} + 3 \hat{j}$ and it is subjected to magnetic field of $4 \hat{k},$ then its

An experimenters diary reads as follows : A charged particle is projected in a magnetic field $(7 \hat{i} - 3 \hat{j}) \times 1 0^{- 3}$ T . The acceleration of the particle is found to be $(\hat{i} + 7 \hat{j}) \times 1 0^{- 6} m s^{- 2}$ then coefficient of $\hat{i}$ is

A charged particle moves with a constant velocity $(\hat{i} + \hat{j}) m / s$ in a magnetic field $B = (2 \hat{i} + 3 \hat{k})$ and uniform electric field $E = (a \hat{i} + b \hat{j} + c \hat{k}) N / C$ , then $($ assuming all quantities in S.I. unit $) :$

If an electron of velocity is $2 i + 4 j$ is subjected to magnetic field of $4 k$ , then, for the electron ,

A proton moving with a velocity of $(6 \hat{i} + 8 \hat{j}) \times 1 0^{5} m s^{- 1}$ enters uniform magnetic field of induction $5 \times 1 0^{- 3} \hat{k} T$ . The magnitude of the force acting on the proton is :
( $\hat{i}, \hat{j}$ and $\hat{k}$ are unit vectors forming a right handed triad)