0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

If $$f_{0} = 5\ cm, \lambda = 600{A^{0}}, a = 1\ cm$$ for a microscope, then what will be its resolving power.

A
$$10.9\times 10^{3} / m$$
B
$$10.9\times 10^{5} / m$$
C
$$10.9\times 10^{4} / m$$
D
$$11.9\times 10^{5} / m$$
Solution
Verified by Toppr

Correct option is B. $$10.9\times 10^{5} / m$$
$$R.P. = \dfrac {2\mu \sin \theta}{1.22\lambda}$$
$$\mu = 1$$
$$\tan \theta \simeq \sin \theta = \dfrac {a}{f} = \dfrac {1}{5} = 0.2\Rightarrow R.D. = \dfrac {2\times 1\times 0.2}{1.22\times 6\times 10^{-7}} = \dfrac {4\times 10^{6}}{3.66}$$
$$RP. = 10.9\times 10^{5} / m$$.

Was this answer helpful?
0
Similar Questions
Q1
If $$f_{0} = 5\ cm, \lambda = 600{A^{0}}, a = 1\ cm$$ for a microscope, then what will be its resolving power.
View Solution
Q2
Resolving power of a microscope can be increased, if
View Solution
Q3
The resolving power of a compound light microscope will be maximum if the source of light is
View Solution
Q4
A microscope is used with sodium light and its resolving power is not sufficiently large.Higher resolution will be obtained by using wavelength of
View Solution
Q5
The resolving power of a compound microscope will increase with
View Solution