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Question

If f={(a,0),(b,2),(c,3)}, g={(a,2),(b,0),(c,1)} then fg=
  1. does not exist
  2. {(a,1),(b,2),(c,4)}
  3. {(a,0),(c,3)}
  4. {(a,3),(b,2),(c,2)}

A
does not exist
B
{(a,3),(b,2),(c,2)}
C
{(a,1),(b,2),(c,4)}
D
{(a,0),(c,3)}
Solution
Verified by Toppr

f={(a,0),(b,2),(c,3)} and g={(a,2),(b,0),(c,1)}

Implies

f(a)=0

f(b)=2

f(c)=3

Similarly

g(a)=2

g(b)=0

g(c)=1

Consider a function

h(x)=f(x)g(x)

Then

h(a)=f(a)g(a)=02=0 ...(i)

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