If five equal pieces of $25 Ω$ are connected in parallel, then their equivalent resistance will be............

Question

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Answer 1

Resistance of each piece :
$R_{1} = R_{2} = R_{3} = R_{4} = R_{5} = 25 Ω$
Equivalent resistance in parallel
$\frac{1}{R _{p}} = \frac{1}{R _{1}} + \frac{1}{R _{2}} + \frac{1}{R _{3}} + \frac{1}{R _{4}} + \frac{1}{R _{5}}$
$∴$ $\frac{1}{R _{p}} = \frac{1}{2 5} + \frac{1}{2 5} + \frac{1}{2 5} + \frac{1}{2 5} + \frac{1}{2 5}$
$⟹ \frac{1}{R _{p}} = \frac{5}{2 5}$
We get,
$R_{p} = 5 Ω$

Answer 2

Resistance of each piece :

R_{1} = R_{2} = R_{3} = R_{4} = R_{5} = 25 Ω

Equivalent resistance in parallel

\frac{1}{R _{p}} = \frac{1}{R _{1}} + \frac{1}{R _{2}} + \frac{1}{R _{3}} + \frac{1}{R _{4}} + \frac{1}{R _{5}}

∴

\frac{1}{R _{p}} = \frac{1}{2 5} + \frac{1}{2 5} + \frac{1}{2 5} + \frac{1}{2 5} + \frac{1}{2 5}

⟹ \frac{1}{R _{p}} = \frac{5}{2 5}

We get,

R_{p} = 5 Ω