If following molecules undergo dimerization then find the value of $\frac{Y Z}{X}$ .
(i) $C l O_{3}$ , (ii) $O F$ , (iii) $G a H_{3}$ , (iv) $A l C l_{3}$ , (v) $I C l_{3}$ , (vi) $B e H_{2}$ , (vii) $N O_{2}$ Where,
$X =$ Number of molecules which are hypervalent in dimeric form.
$Y =$ Number of molecules which com octet in dimer form.
$Z =$ Number of molecules which are hypovalent in dimeric form.

Question

If following molecules undergo dimerization then find the value of $\frac{Y Z}{X}$ .
(i) $C l O_{3}$ , (ii) $O F$ , (iii) $G a H_{3}$ , (iv) $A l C l_{3}$ , (v) $I C l_{3}$ , (vi) $B e H_{2}$ , (vii) $N O_{2}$ Where,
$X =$ Number of molecules which are hypervalent in dimeric form.
$Y =$ Number of molecules which com octet in dimer form.
$Z =$ Number of molecules which are hypovalent in dimeric form.

Toppr Admin · Accepted Answer

On formation of dimer-ClO3-ICl3 are hypervalent in dimeric form -X-OF-NO2 have completed their octet -Y-GaH3-AlCl3-BeH2 are hypovalent in dimeric form-Thus- X-2-Y-2-Z-3YZX-2-xD7-32-3

On formation of dimer,ClO3,ICl3 are hypervalent in dimeric form (X).OF,NO2 have completed their octet (Y).GaH3,AlCl3,BeH2 are hypovalent in dimeric form.Thus, X=2,Y=2,Z=3YZX=2×32=3

On formation of dimer,
$C l O_{3}, I C l_{3}$ are hypervalent in dimeric form (X).

$O F, N O_{2}$ have completed their octet (Y).

$G a H_{3}, A l C l_{3}, B e H_{2}$ are hypovalent in dimeric form.

Thus, $X = 2, Y = 2, Z = 3$

$\frac{Y Z}{X} = \frac{2 \times 3}{2} = 3$