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Standard XII
Chemistry
Real Gases
Question
If force of attraction between the gas molecules is negligible, vander Waal's equation (for one 1 mole) will become?
P
V
=
R
T
+
P
b
P
V
=
R
T
V
−
b
−
a
V
2
P
V
=
R
T
+
a
/
V
P
V
=
R
T
−
a
/
V
A
P
V
=
R
T
V
−
b
−
a
V
2
B
P
V
=
R
T
+
P
b
C
P
V
=
R
T
+
a
/
V
D
P
V
=
R
T
−
a
/
V
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Similar Questions
Q1
Match the van der Waal's equation for one mole of gas given in column B to the conditions given in column A.
Column A
Column B
(A) High pressure
(i)
P
V
=
R
T
+
P
b
(B) Low pressure
(ii)
P
V
=
R
T
−
a
V
(C)
P
→
0
(iii)
P
V
=
R
T
(D) Neither
a
nor
b
is negligible
(iv)
(
P
+
a
V
2
)
(
V
−
b
)
=
R
T
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Q2
In a gas equation,
PV = RT
, V refers to the volume of:
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Q3
In the gas equation
P
V
=
R
T
, V is the volume of
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Q4
In the gas equation PV = RT, V represents the volume of :
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Q5
PV=RT. (P+a/v
2
)(v-b)=Rt where p-pressure, v-volume, R-gas constant, T-temperature. Find dimensions of a and b.
View Solution