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Standard XII
Physics
Question
If
(
f
o
r
c
e
)
x
=
(
M
a
s
s
)
2
(
r
a
d
i
u
s
)
2
(
t
i
m
e
p
e
r
i
o
d
)
4
, then the value of
x
is
1
2
3
4
A
3
B
4
C
2
D
1
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Solution
Verified by Toppr
(
f
o
r
c
e
)
x
=
(
M
a
s
s
)
2
(
r
a
d
i
u
s
)
2
p
4
(
M
1
L
1
T
−
2
)
x
=
M
2
L
2
T
−
4
⇒
x
=
2
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