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Question

If $f (x) = a x^{5} + b x^{3} + c x + d$ is odd then
$b = 0$
$a = 0$
$c = 0$
$d = 0$

A

d = 0

B

b = 0

C

c = 0

D

a = 0

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Solution

Verified by Toppr

For odd function
$f (- x) = - f (x)$
$a (- x)^{5} + b (- x)^{3} + c (- x) + d = - a x^{5} - 6 x^{3} - c x^{3} - d$
$\Rightarrow d = 0$

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