If - g - is the acceleration due to gravity on the earth-s surface- the change in the potential energy of an object of mass m raised from the surface of the earth to a height equal to the radius R of the earth isdisplaystyle dfrac - mgR - 2 - displaystyle - 2mgR -displaystyle - mgR -displaystyle - -mgR -

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Toppr Admin · Accepted Answer

Gain in potential energy-x25B3-U-U2-x2212-U1-x25B3-U-x2212-GMm2R-x2212-x2212-GMmR-

If $g$ is the acceleration due to gravity on the earth's surface, the change in the potential energy of an object of mass $m$ raised from the surface of the earth to a height equal to the radius $R$ of the earth is
$\frac{m g R}{2}$
$2 m g R$
$m g R$
$- m g R$

$Gain in potential energy = △ U = U_{2} - U_{1}$
$△ U = (- \frac{G M m}{2 R}) - (- \frac{G M m}{R})$

If g is the acceleration due to gravity on the earth's surface, the change in the potential energy of an object of mass m raised from the surface of the earth to a height equal to the radius R of the earth ismgR22mgRmgR−mgR

Gain in potential energy=△U=U2−U1△U=(−GMm2R)−(−GMmR)

If $g$ is the acceleration due to gravity on the earth's surface, the change in the potential energy of an object of mass $m$ raised from the surface of the earth to a height equal to the radius $R$ of the earth is
$\frac{m g R}{2}$
$2 m g R$
$m g R$
$- m g R$

$Gain in potential energy = △ U = U_{2} - U_{1}$
$△ U = (- \frac{G M m}{2 R}) - (- \frac{G M m}{R})$