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Question

If i = $\sqrt{- 1}, t h e n 1 + i^{2} + i^{3} - i^{6} + i^{8}$ is equal to -
2- i
1
-3
-1

A

2- i

B

1

C

-3

D

-1

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Solution

Verified by Toppr

Given, $i = \sqrt{- 1}$
$∴ 1 + i^{2} + i^{3} - i^{6} + i^{8} = 1 - 1 - i + 1 + 1$
$= 2 - i$

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If i =

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