0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

If Kc for the formation of ammonia is 2 mol2 L2,Kc for the decomposition of ammonia is:
  1. 0.5 mol2/L2
  2. 0.25 mol2/L2
  3. 0.75 mol2/L2
  4. none of these

A
none of these
B
0.25 mol2/L2
C
0.5 mol2/L2
D
0.75 mol2/L2
Solution
Verified by Toppr

If the equilibrium constant for the forward reaction is K, then the equilibrium constant for the reverse reaction is 1K

Was this answer helpful?
0
Similar Questions
Q1
If Kc for the formation of ammonia is 2 mol2 L2,Kc for the decomposition of ammonia is:
View Solution
Q2
Assertion :For reaction N2(g)+3H2(g)2NH3(g) Unit of KC=L2mol2 Reason: For the reaction N2(g)+3H2(g)2NH3(g), Equilibrium constant KC=[NH3]2[N2][H2]3
View Solution
Q3
If Kc for the formation of HI from H2 and I2 is 48, then Kc for decomposition of 1 mole of HI is ................
View Solution
Q4

N2(g)+3H2(g)2NH3(g)
Value of Kc for the formation of ammonia according to the above equation is :

View Solution
Q5
If two lines have direction cosines l1,m1,n1 and l2,m2,n2 then the condition for these lines being perpendicular to each other would be -
View Solution