A ray of light is coming along the line $L = 0$ and strikes the plane mirror kept along the plane $P = 0$ at $B$ . $A (2, 1, 6)$ is a point on the line $L = 0$ whose image about $P = 0$ is A′. It is given that $L = 0$ is $(x - 2) / 3 = (y - 1) / 4 = (z - 6) / 5$ and $P = 0$ is $x + y - 2 z = 3$
If $L_{1} = 0$ is the reflected ray, then its equation is
$\frac{x + 10}{4} = \frac{y - 5}{4} = \frac{z + 2}{3}$
$\frac{x + 10}{3} = \frac{y + 15}{5} = \frac{z + 14}{5}$
$\frac{x + 10}{4} = \frac{y + 15}{5} = \frac{z + 14}{3}$
None of these

Question

A ray of light is coming along the line $L = 0$ and strikes the plane mirror kept along the plane $P = 0$ at $B$ . $A (2, 1, 6)$ is a point on the line $L = 0$ whose image about $P = 0$ is A′. It is given that $L = 0$ is $(x - 2) / 3 = (y - 1) / 4 = (z - 6) / 5$ and $P = 0$ is $x + y - 2 z = 3$
If $L_{1} = 0$ is the reflected ray, then its equation is
$\frac{x + 10}{4} = \frac{y - 5}{4} = \frac{z + 2}{3}$
$\frac{x + 10}{3} = \frac{y + 15}{5} = \frac{z + 14}{5}$
$\frac{x + 10}{4} = \frac{y + 15}{5} = \frac{z + 14}{3}$
None of these

Toppr Admin · Accepted Answer