0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

If mass of earth is 5.98×1024 kg and earth moon distance is 3.8×105 km, the orbital period of moon, in days is
  1. 8.1 days
  2. 81 days
  3. 27 days
  4. 2.7 days

A
8.1 days
B
81 days
C
27 days
D
2.7 days
Solution
Verified by Toppr

The correct option is A 27 days
M=5.98×1024kg

R=3.8×108km

The orbital time period of moon,

T=2πR3GM

T=2×3.14(3.8)3×10246.67×1011×5.48×1024

T=23.2427×105sec

In days,

Time period, T=23.2427×10560×60×24day

T=27 days

The correct option is A.

Was this answer helpful?
4
Similar Questions
Q1
If mass of earth is 5.98×1024 kg and earth moon distance is 3.8×105 km, the orbital period of moon, in days is
View Solution
Q2
The mass of the earth is 6×1024 kg and that of the moon is 7.4×1022 kg. If the distance between the earth and the moon is 3.8×105 km. calculate the force exerted by the earth.
View Solution
Q3
The orbital radius of moon around the earth is 3.8×108 meter and its time period is 27.3 days. The centripetal acceleration of moon will be
View Solution
Q4
If the mass of earth were 4 times the present mass, the mass of the moon were half the present mass and the moon was revolving round the earth at twice the present distance, the time period of revolving of the moon would be (in days)
(Take the normal time period of moon be 28 days)
View Solution
Q5
The moon is about 3.8×105 Km from the centre of the earth. It takes about 27 days for completing the orbit around the earth. Calculate the speed of moon in Km per day.
View Solution