Solve Study Textbooks Guides

Use app

Login

>>Class 11
>>Physics
>>Gravitation
>>Gravitational Potential Energy
>> $If Me is the mass of earth and Mm is the$

Question

If $M_{e}$ is the mass of earth and $M_{m}$ is the mass of moon $(M_{e} = 81 M_{m})$ . The potential energy associated with object of mass $m$ situated at a distance $R$ from the centre of earth and $r$ from the centre of moon, will be :

A

$- G m M_{m} [\frac{R}{8 1} + r] \frac{1}{R ^{2}}$

B

$- G m M_{m} [\frac{8 1}{r} + \frac{1}{R}]$

C

$- G m M_{m} [\frac{8 1}{R} + \frac{1}{r}]$

D

$- G m M_{m} [\frac{8 1}{R} - \frac{1}{r}]$

Medium

Open in App

Updated on : 2022-09-05

Solution

Verified by Toppr

Correct option is C)

Gravitational $P . E = - \frac{G M m}{r}$

Gravitational $P . E$ at O= $P . E_{E} + P . E_{m}$

$P . E_{o} = (- \frac{G M _{E} m}{R}) + (- \frac{G M _{m} m}{r})$

Given: $M_{E} = 81 M_{m}$

$P . E_{o} = - \frac{G ( 8 1 M _{m} ) m}{R} - \frac{G M _{m} m}{r}$

$P . E_{o} = - G m M_{m} [\frac{8 1}{R} + \frac{1}{r}]$

solution

Was this answer helpful?

0

0

Similar questions

The mass of the moon is 1% of mass of the earth.The ratio of gravitational pull of earth on moon to that of moon on earth will be:

The minimum speed with which a body is projected from the surface of the earth so that it reaches to the surface of the moon is v while the minimum speed with which a body is projected from the surface of the moon so that it reaches to the surface of the earth is v'. Then, disregarding the spinning and orbital motions of the earth and the moon, and using the fact that $\frac{M _{E}}{R _{E}} > \frac{M _{M}}{R _{M}}$ where $M_{E}, M_{M}, R_{E}$ and $R_{M}$ are mass of earth, mass of moon, radius of earth and radius of the moon respectively, we can say that :

If the distance between the centres of earth and moon is $D$ and mass of earth is $81$ times that of moon. At what distance from the centre of earth gravitational field will be zero.

The distance between the centres of the Moon and the earth is $D$ . The mass of the earth is $81$ times the mass of the Moon. At what distance from the centre of the earth, the gravitational force will be zero?

The gravitational potential energy of a body at a distance $r$ from the centre of earth is $U$ . Its weight at a distance $2 r$ from the centre of earth is

More From Chapter

View chapter >

Revise with Concepts

Gravitational Potential

ExampleDefinitionsFormulaes

Gravitational Potential Energy

ExampleDefinitionsFormulaes

Gravitational Potential Energy- Medium

ExampleDefinitionsFormulaes

Potential Energy Between Two Point Masses and System of Point Masses

ExampleDefinitionsFormulaes

Changing Configuration of a System

ExampleDefinitionsFormulaes

Gravitational Potential Energy - L2

ExampleDefinitionsFormulaes

View more

Learn with Videos

Introduction to gravitational potential

Gravitational potential due to point mass

Gravitational potential due to uniform ring

Gravitational potential due to spherical shell

Gravitational potential due to solid sphere

Introduction to gravitational potential energy

Gravitational potential energy due to continuous mass system

Gravitational potential energy

Gravitational Potential Energy for System of Particles

Problems on Gravitational Potential Energy

Practice more questions

JEE Mains Questions

AIIMS Questions

Medium Questions