If - -nP-r-336- -n- C-r-56- Find n and r and hence - -n-1- C-r-1-

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If $${ }^nP_{r}=336,{ }^{n} C_{r}=56$$. Find $$n$$ and $$r$$ and hence find $${ }^{n-1} C_{r-1}$$.

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If $^{n} P_{r} = 336,^{n} C_{r} = 56$ , then find n and r and hence find $^{n - 1} C_{r - 1}$

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If ⁿP_r = 336 and ⁿC_r = 56 find n and r.

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if ncr=56 and npr=336 find n

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^{n} P_{r} =^{n} P_{r + 1}

and

^{n} C_{r} =^{n} C_{r - 1}

, find n and r.

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Given:
(i)

^{n} c_{p} = ∠ r^{n} c_{r}

(ii)

^{n} c_{r} +^{n} c_{r - 1} =^{n + 1} c_{r}

^{n} p_{r} = 720

and

^{n} c_{r} = 120

, then what is the value of 'r'

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