If OA - 5 cm- AB - 8 cm and OD is perpendicular to AB- then CD is equal to-3 cm4 cm5 cm2 cm

Question

Toppr Admin · Accepted Answer

Given- OA-5 cm- AB-8 cmAnd OD is perpendicular to AB- so AC-CB-8-2-4cmIn triangle ACO-xA0-AO2-AC2-CO2- by using pythagoras theorem- we get25-16-CO2CO-3 cmOD- radius -5cmCD-OD-x2212-OC-5-x2212-3-2 cm

If $O A = 5$ cm, $A B = 8$ cm and $O D$ is perpendicular to $A B$ , then $C D$ is equal to:

$3$ cm
$4$ cm
$5$ cm
$2$ cm

Given, $O A = 5$ cm, $A B = 8$ cm
And $O D$ is perpendicular to $A B,$ so $A C = C B = 8 / 2 = 4 c m$
In triangle $A C O,$
$A O^{2} = A C^{2} + C O^{2}$ , by using pythagoras theorem, we get
$25 = 16 + C O^{2}$
$C O = 3$ cm
$O D =$ radius $= 5$ cm
$C D = O D - O C = 5 - 3 = 2$ cm

If OA=5 cm, AB=8 cm and OD is perpendicular to AB, then CD is equal to:3 cm4 cm5 cm2 cm

Given, OA=5 cm, AB=8 cmAnd OD is perpendicular to AB, so AC=CB=8/2=4cmIn triangle ACO, AO2=AC2+CO2, by using pythagoras theorem, we get25=16+CO2CO=3 cmOD= radius =5cmCD=OD−OC=5−3=2 cm

If $O A = 5$ cm, $A B = 8$ cm and $O D$ is perpendicular to $A B$ , then $C D$ is equal to:

$3$ cm
$4$ cm
$5$ cm
$2$ cm

Given, $O A = 5$ cm, $A B = 8$ cm
And $O D$ is perpendicular to $A B,$ so $A C = C B = 8 / 2 = 4 c m$
In triangle $A C O,$
$A O^{2} = A C^{2} + C O^{2}$ , by using pythagoras theorem, we get
$25 = 16 + C O^{2}$
$C O = 3$ cm
$O D =$ radius $= 5$ cm
$C D = O D - O C = 5 - 3 = 2$ cm