If p- q are the roots of equation x-2 - px - q - 0- then the value of p must be equal to0-1121- -2

Question

Toppr Admin · Accepted Answer

Given equation-xA0-x2-px-qAlso- given p-q are the roots of the equation-p-q-x2212-p -xA0- 2p-x2212-q -xA0- -xA0-1-And -xA0- pq-qq-p-x2212-1-0-x21D2-q-0 or p-1So- by -1-xA0-q-0-x21D2-p-0 -xA0-Hence- the values of p are 0-1-

If $p, q$ are the roots of equation $x^{2} + p x + q = 0$ , then the value of $p$ must be equal to
$0, 1$
$1$
$2$
$1, - 2$

Given equation
$x^{2} + p x + q$
Also, given $p, q$ are the roots of the equation.
$p + q = - p$
$2 p = - q$ ..... $(1)$
And $p q = q$
$q (p - 1) = 0$
$\Rightarrow q = 0$ or $p = 1$
So, by $(1)$ , $q = 0 \Rightarrow p = 0$
Hence, the values of $p$ are $0, 1$ .

If p,q are the roots of equation x2+px+q=0, then the value of p must be equal to0,1121,−2

Given equation x2+px+qAlso, given p,q are the roots of the equation.p+q=−p 2p=−q .....(1)And pq=qq(p−1)=0⇒q=0 or p=1So, by (1), q=0⇒p=0 Hence, the values of p are 0,1.

If $p, q$ are the roots of equation $x^{2} + p x + q = 0$ , then the value of $p$ must be equal to
$0, 1$
$1$
$2$
$1, - 2$

Given equation
$x^{2} + p x + q$
Also, given $p, q$ are the roots of the equation.
$p + q = - p$
$2 p = - q$ ..... $(1)$
And $p q = q$
$q (p - 1) = 0$
$\Rightarrow q = 0$ or $p = 1$
So, by $(1)$ , $q = 0 \Rightarrow p = 0$
Hence, the values of $p$ are $0, 1$ .