If pparallel qparallel r- x- y- z from given figure-

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Toppr Admin · Accepted Answer

By sum of interior angle- -x2235-p-x2225-q-y-55o-180o-xA0-This gives-y-135oNow- -x2220-x and 55o are alternating angle -x2235-p-x2225-r-x2234-x-55oAlso- given triangle is a right angled triangle-x2234-z-x-90o-180oz-180o-x2212-90o-x2212-55o-35o

If $p ∥ q ∥ r$ , find $x, y, z$ from given figure.

By sum of interior angle. ( $∵ p ∥ q$ )
$y + 55^{o} = 180^{o}$
This gives;
$y = 135^{o}$

Now, $∠ x$ and $55^{o}$ are alternating angle ( $∵ p ∥ r)$
$∴ x = 55^{o}$

Also, given triangle is a right angled triangle.
$∴ z + x + 90^{o} = 180^{o}$
$z = 180^{o} - 90^{o} - 55^{o} = 35^{o}$

If p∥q∥r, find x,y,z from given figure.

By sum of interior angle. (∵p∥q)y+55o=180o This gives;y=135oNow, ∠x and 55o are alternating angle (∵p∥r)∴x=55oAlso, given triangle is a right angled triangle.∴z+x+90o=180oz=180o−90o−55o=35o

If $p ∥ q ∥ r$ , find $x, y, z$ from given figure.

By sum of interior angle. ( $∵ p ∥ q$ )
$y + 55^{o} = 180^{o}$
This gives;
$y = 135^{o}$

Now, $∠ x$ and $55^{o}$ are alternating angle ( $∵ p ∥ r)$
$∴ x = 55^{o}$

Also, given triangle is a right angled triangle.
$∴ z + x + 90^{o} = 180^{o}$
$z = 180^{o} - 90^{o} - 55^{o} = 35^{o}$