In a right angle triangle ABC with sides a- b- c-If pythagoras theorem states that displaystyle - a - 2 - b - 2 - c - 2 - then which of the following is true-displaystyle c-sqrt - - a - 2 - b - 2 - - displaystyle c-sqrt - - a - 2 - - - b - 2 -displaystyle c-sqrt - - a - 2 - - times - b - 2 -displaystyle c-sqrt - - a - 2 - - div - b - 2 -

Question

In a right angle triangle  ABC with sides a- b- c-If pythagoras theorem states that displaystyle - a - 2 - b - 2 - c - 2 - then which of the following is true-displaystyle c-sqrt - - a - 2 - b - 2 - - displaystyle c-sqrt - - a - 2 - - - b - 2 -displaystyle c-sqrt - - a - 2 - - times - b - 2 -displaystyle c-sqrt - - a - 2 - - div - b - 2 -

Toppr Admin · Accepted Answer

If a2-b2-c2- then-xA0- is-xA0-c-x221A-a2-b2Therefore- A is the correct answer-

In a right angle triangle $A B C$ with sides $a, b, c;$
If pythagoras theorem states that $a^{2} + b^{2} = c^{2}$ then which of the following is true:

$c = \sqrt{a^{2} + b^{2}}$
$c = \sqrt{a^{2}} - b^{2}$
$c = \sqrt{a^{2}} \times b^{2}$
$c = \sqrt{a^{2}} \div b^{2}$

If $a^{2} + b^{2} = c^{2}$ , then is $c = \sqrt{a^{2} + b^{2}}$
Therefore, A is the correct answer.

In a right angle triangle ABC with sides a,b,c;If pythagoras theorem states that a2+b2=c2 then which of the following is true:c=√a2+b2c=√a2−b2c=√a2×b2c=√a2÷b2

If a2+b2=c2, then is c=√a2+b2Therefore, A is the correct answer.

In a right angle triangle $A B C$ with sides $a, b, c;$
If pythagoras theorem states that $a^{2} + b^{2} = c^{2}$ then which of the following is true:

$c = \sqrt{a^{2} + b^{2}}$
$c = \sqrt{a^{2}} - b^{2}$
$c = \sqrt{a^{2}} \times b^{2}$
$c = \sqrt{a^{2}} \div b^{2}$

If $a^{2} + b^{2} = c^{2}$ , then is $c = \sqrt{a^{2} + b^{2}}$
Therefore, A is the correct answer.