If Q inversely varies as square of P and Q - 8 when P - 2- Q when P - 2sqrt -3-

Question

Toppr Admin · Accepted Answer

Since Q-x221D-1P2- we getQp2-k-k a constantPutting Q-8 and P-2- we obtain k-8-xD7-22-32- HenceQP2-32-Putting P-2-x221A-3 in this relation we obtainQ-32-x221A-3-2-3212-83-

If $Q$ inversely varies as square of $P$ and if $Q = 8$ when $P = 2$ , find $Q$ when $P = 2 \sqrt{3}$

Since $Q \propto \frac{1}{P^{2}}$ , we get
$Q p^{2} = k, k$ a constant
Putting $Q = 8$ and $P = 2$ , we obtain $k = 8 \times 2^{2} = 32$ . Hence
$Q P^{2} = 32$ .
Putting $P = 2 \sqrt{3}$ in this relation we obtain
$Q = \frac{32}{(\sqrt{3})^{2}} = \frac{32}{12} = \frac{8}{3}$ .

If Q inversely varies as square of P and if Q=8 when P=2, find Q when P=2√3

Since Q∝1P2, we getQp2=k,k a constantPutting Q=8 and P=2, we obtain k=8×22=32. HenceQP2=32.Putting P=2√3 in this relation we obtainQ=32(√3)2=3212=83.

If $Q$ inversely varies as square of $P$ and if $Q = 8$ when $P = 2$ , find $Q$ when $P = 2 \sqrt{3}$

Since $Q \propto \frac{1}{P^{2}}$ , we get
$Q p^{2} = k, k$ a constant
Putting $Q = 8$ and $P = 2$ , we obtain $k = 8 \times 2^{2} = 32$ . Hence
$Q P^{2} = 32$ .
Putting $P = 2 \sqrt{3}$ in this relation we obtain
$Q = \frac{32}{(\sqrt{3})^{2}} = \frac{32}{12} = \frac{8}{3}$ .