If R is the radius of the earth and g the acceleration due to gravity on the earth-s surface- then mean density of the earth is-dfrac-4pi G-3gR-dfrac-3pi R-4gG-dfrac-3g-4pi RG-dfrac-rg-12RG-

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Toppr Admin · Accepted Answer

We know-xA0-F-GMmR2

If $R$ is the radius of the earth and $g$ the acceleration due to gravity on the earth's surface, then mean density of the earth is:
$\frac{4 π G}{3 g R}$
$\frac{3 π R}{4 g G}$
$\frac{3 g}{4 π R G}$
$\frac{r g}{12 R G}$

We know, $F = \frac{G M m}{R^{2}}$

If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, then mean density of the earth is:4πG3gR3πR4gG3g4πRGrg12RG

We know, F=GMmR2

If $R$ is the radius of the earth and $g$ the acceleration due to gravity on the earth's surface, then mean density of the earth is:
$\frac{4 π G}{3 g R}$
$\frac{3 π R}{4 g G}$
$\frac{3 g}{4 π R G}$
$\frac{r g}{12 R G}$

We know, $F = \frac{G M m}{R^{2}}$