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Standard XII
Mathematics
Question
If
sec
2
θ
+
tan
2
θ
+
1
=
2
, then find the value of
sec
(
−
θ
)
:
−
2
−
1
2
1
±
1
A
1
B
−
1
2
C
−
2
D
±
1
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Solution
Verified by Toppr
Given :
sec
2
θ
+
tan
2
θ
+
1
=
2
⟹
1
cos
2
θ
+
sin
2
θ
cos
2
θ
+
1
=
2
⟹
1
+
sin
2
θ
+
c
o
s
2
θ
=
2
cos
2
θ
⟹
1
+
1
=
2
c
o
s
2
θ
⟹
c
o
s
2
θ
=
1
⟹
cos
θ
=
±
1
∵
cos
(
−
θ
)
=
cos
θ
∴
sec
(
−
θ
)
=
sec
(
θ
)
=
1
cos
θ
=
±
1
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