0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

# If the activity of 108Ag is 3 micro curie, the number of atoms present in it are ( λ= 0.005 sec−1)2.2 x 1052.2 x 1062.2 x 1042.2 x 107

A
2.2 x 106
B
2.2 x 107
C
2.2 x 104
D
2.2 x 105
Solution
Verified by Toppr

#### λ=0.005sec−11 Micro curie =3.7×104dpsAssuming all Ag atoms to be radioactive, and each showing Let no of atoms present =1 dps noGiven:(dNdt)activity=λN0⇒3.7×3×104dps=0.005×N0⇒N0=2.2×107atoms

1
Similar Questions
Q1
If the activity of 108Ag is 3 micro curie, the number of atoms present in it are ( λ= 0.005 sec1)
View Solution
Q2

An engine can pump 30,000 litres of water to a vertical height of 45 metres in 10 minutes. Calculate the power. Take g= 9.8 m s-1 [Density of water = 103 kg m-3 1000 liters = 1 m3]

View Solution
Q3
The pressure that has to be applied to the ends of a steel wire of length 10 cm to keep its length constant when its temperature is raised by 100C is:-
Given: Y=2×1011 N/m2 and α=1.1×105 /C
View Solution
Q4
The pressure that has to be applied to the ends of a steel wire of length 10 cm to keep its length constant when its temperature is raised by 100Cis(ForsteelY=2×1011Nm2 and α=1.1×105K1)
View Solution
Q5
If we have a pure Na2SO4.5H2O sample and it contains 2.2×1010 electrons, the mass of the sample is x×1014 g. x is
View Solution