If the area of a circle is A- radius of the circle is r and circumference of it is C- thenrC - 2Adisplaystyle frac-C-A-frac-r-2-displaystyle AC-frac-r-2-4-displaystyle frac-A-r-C

Question

Toppr Admin · Accepted Answer

A-x3C0-r2-r-xD7-2-x3C0-r-2-rC2-x21D2-rC-2A

If the area of a circle is $A$ , radius of the circle is $r$ and circumference of it is $C$ , then
$r C = 2 A$
$\frac{C}{A} = \frac{r}{2}$
$A C = \frac{r^{2}}{4}$
$\frac{A}{r} = C$

$A = π r^{2}$
$= \frac{r \times (2 π r)}{2} = \frac{r C}{2}$
$\Rightarrow r C = 2 A$

If the area of a circle is A, radius of the circle is r and circumference of it is C, thenrC=2ACA=r2AC=r24Ar=C

A=πr2=r×(2πr)2=rC2⇒rC=2A

If the area of a circle is $A$ , radius of the circle is $r$ and circumference of it is $C$ , then
$r C = 2 A$
$\frac{C}{A} = \frac{r}{2}$
$A C = \frac{r^{2}}{4}$
$\frac{A}{r} = C$

$A = π r^{2}$
$= \frac{r \times (2 π r)}{2} = \frac{r C}{2}$
$\Rightarrow r C = 2 A$