If the area of a rectangle is 48 sq.m and its diagonal is 10 m, then find its length, breadth, and perimeter.
Let length and breadth of rectangle be ′l′ and ′b′ respectively. Then,
Area of rectangle =48 m2
=l×b=48 m2⇒l=48b⟶(1)
and l2+b2=(10)2=100
from (1), l=48b, we get
(48b)2+b2=100⇒2304b2+b2=100
⇒b4−100b2+2304=0
after solving, b=8 or 6
If b=8, then l=488=6 &
If b=6, then l=486=8
Perimeter =2(l+b)
=2(6+8)=28 m