If the charge of 10μC and −2μC are given to two plates of a capacitor which are connected across a battery of 12V, find the capacitance of the capacitor.
0.33μF
0.66μF
0.41μF
0.5μF
A
0.33μF
B
0.5μF
C
0.41μF
D
0.66μF
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Solution
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Capacitance of of capacitor with different charges on plates is given by:
C=Q1−Q22V
Substituting values,
C=10−(−2)2×12=0.5μF
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