The maximum length of chord = Diameter of circle C1=8 units
Now, equation of the chord of slope 34,
3x−4y=0.
The center of circle C2 must be on the line perpendicular to the chord.
So, the center of the circle C2 can be written as (3a,−4a)
x1=3a,y1=−4a
Where a common factor.
As the chord shown in image, we get AB=5 units using pythagoras theorem.
Hence,
Using sectional formula from a point to a line,
3×(3a)5−4×(−4a)5=8−5
25a=15
=>a=35.
Now,
The center of the circle C2 can be written as (3×35,−4×35)=(95,−125).