If the circumference the base of a right circular cone and the slant height are 120pi cm and 10cm respectively- then the curved surface area of the cone is equal to-1200pi -cm-2-600pi -cm-2-300pi -cm-2-600 -cm-2-

Question

Toppr Admin · Accepted Answer

Given-circumference -120-x3C0-xA0-cm and slant height-l-10-xA0-cm-x21D2-2-x3C0-r-120-x3C0-x21D2-2r-120-x21D2-r-60-xA0-cm-We know- the curved surface area of the cone-xA0-x3C0-rl-x3C0-xD7-60-xD7-10-600-x3C0-xA0-cm2Hence- option B is correct-

If the circumference at the base of a right circular cone and the slant height are $120 π$ $c m$ and $10 c m$ respectively, then the curved surface area of the cone is equal to:
$1200 π$ ${c m}^{2}$
$600 π$ ${c m}^{2}$
$300 π$ ${c m}^{2}$
$600$ ${c m}^{2}$

Given,
circumference $= 120 π c m$ and slant height $(l) = 10 c m$
$\Rightarrow 2 π r = 120 π$
$\Rightarrow 2 r = 120$
$\Rightarrow r = 60 c m$ .

We know, the curved surface area of the cone $= π r l$ .
$= π \times 60 \times 10$
$= 600 π c m^{2}$

Hence, option $B$ is correct.

If the circumference at the base of a right circular cone and the slant height are 120π cm and 10cm respectively, then the curved surface area of the cone is equal to:1200π cm2600π cm2300π cm2600 cm2

Given,circumference =120π cm and slant height(l)=10 cm⇒2πr=120π⇒2r=120⇒r=60 cm.We know, the curved surface area of the cone =πrl.=π×60×10=600π cm2Hence, option B is correct.

If the circumference at the base of a right circular cone and the slant height are $120 π$ $c m$ and $10 c m$ respectively, then the curved surface area of the cone is equal to:
$1200 π$ ${c m}^{2}$
$600 π$ ${c m}^{2}$
$300 π$ ${c m}^{2}$
$600$ ${c m}^{2}$

Given,
circumference $= 120 π c m$ and slant height $(l) = 10 c m$
$\Rightarrow 2 π r = 120 π$
$\Rightarrow 2 r = 120$
$\Rightarrow r = 60 c m$ .

We know, the curved surface area of the cone $= π r l$ .
$= π \times 60 \times 10$
$= 600 π c m^{2}$

Hence, option $B$ is correct.