If the curved surface area of a solid right circular cylinder of height h and radius r is one-third of its total surface area, then
h=13r
h=12r
h=r
h=2r
A
h=12r
B
h=r
C
h=13r
D
h=2r
Open in App
Solution
Verified by Toppr
We know, curved surface area of a cylinder of radius "R" and height "h" =2πRh Total surface area of a cylinder of radius "r" and height "h" =2πr(r+h) Given, 2πRh=13×2πr(r+h) ∴h=13×(r+h) ∴23h=13r ∴h=12r
Was this answer helpful?
17
Similar Questions
Q1
If the curved surface area of a solid right circular cylinder of height h and radius r is one-third of its total surface area, then
View Solution
Q2
In each example given below, radius of base of a cylinder and its height are given. Then find the curved surface area and total surface area.
(1) r = 7 cm, h = 10 cm
(2) r = 1.4 cm, h = 2.1 cm
(3) r = 2.5 cm, h = 7 cm
(4) r = 70 cm, h = 1.4 cm
(5) r = 4.2 cm, h = 14 cm
View Solution
Q3
The total surface area of a solid right cylinder of radius r and height h is 2πr(h+r)
View Solution
Q4
Curved surface area of cylinder of radius r and height h is:
View Solution
Q5
Write the ratio of total surface area to the curved surface area of a cylinder of radius r and height h.