If the density of a certain gas 30-oC and 768 torr is 1-35 kg-m-3- the density STP would be-1-48 kg-m-3-1-58 kg-m-3-1-25 kg-m-3-1-4 kg-m-3-

Question

If the density of a certain gas 30-oC and 768  torr is 1-35  kg-m-3- the density STP would be-1-48  kg-m-3-1-58  kg-m-3-1-25  kg-m-3-1-4  kg-m-3-

Toppr Admin · Accepted Answer

From Ideal gas law-PM-dRTP1-768-xA0-torrT1-300-xA0-C-303-xA0-Kd1-1-35kg-m3At STP-xA0-T2-273-xA0-KP2-760-xA0-torrP1P2-d1T1d2T2768760-1-35-xD7-303d2-xD7-273d2-1-48kg-m3Hence- option A is correct-

Mass(kg)	Volume $(m^{3})$	Density $(k g / m^{3})$
350	175	x
y	190	4

If the density of a certain gas at 30oC and 768 torr is 1.35 kg/m3, the density at STP would be:1.48 kg/m31.58 kg/m31.25 kg/m31.4 kg/m3

From Ideal gas law,PM=dRTP1=768 torrT1=300 C=303 Kd1=1.35kg/m3At STP, T2=273 KP2=760 torrP1P2=d1T1d2T2768760=1.35×303d2×273d2=1.48kg/m3Hence, option A is correct.

If the density of a certain gas at $30^{o} C$ and $768 t o r r$ is $1.35 k g / m^{3}$ , the density at STP would be:
$1.48 k g / m^{3}$
$1.58 k g / m^{3}$
$1.25 k g / m^{3}$
$1.4 k g / m^{3}$